Concept 2

Solve percent increase/decrease problems and use growth factors.

Core Idea

A percent increase or decrease is fastest handled with a single multiplication using the growth factor: multiply by (1 + r) for an increase or (1 − r) for a decrease.

Understanding

When a quantity increases by 20%, you don't have to find 20% and then add it. Just multiply by 1.20 in one step. That multiplier — 1 +𝑟 for an increase, 1 𝑟 for a decrease — is called the growth factor.

New Value=Original×(1±𝑟)

A shirt was $80 and its price rose 15%:

80 ×1.15 =92

A population of 5,000 fell by 12%:

5,000 ×0.88 =4,400

To find the percent change when you already have both values:

Percent Change=NewOriginalOriginal×100%

The denominator is always the original value — the value you started from. This is where errors cluster. If a price goes from $50 to $60, the increase is based on 50, not 60.

For repeated changes (e.g., 10% increase each year for 3 years), multiply the growth factor repeatedly:

Final =Original ×(1.10)3

Don't add the percents (30% over 3 years) — compounding means each increase builds on the previous result.

Step by Step

  1. Identify the original value and the percent change.
  2. Convert the percent to a decimal r.
  3. Choose the growth factor: (1 + r) for increase, (1 − r) for decrease.
  4. Multiply: New = Original × growth factor. For repeated changes, raise the factor to the appropriate power.

Misconceptions

  • Adding percents for successive changes — e.g., saying two consecutive 10% increases equal a 20% increase (it's actually 21%).
  • Using the new value as the base when computing percent change instead of the original value.
  • Computing the percent of the change correctly but forgetting to add it back (or subtract it) from the original.
Question

Worked Example

The population of a town was 20,000 in 2020. It increased by 10% from 2020 to 2021 and then decreased by 10% from 2021 to 2022. What was the population in 2022?

Select an answer to see the explanation